20x^2=11x

Solution for 20x^2=11x equation:

20x^2=11x

We move all terms to the left:

20x^2-(11x)=0

a = 20; b = -11; c = 0;
Δ = b2-4ac
Δ = -112-4·20·0
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{121}=11$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-11}{2*20}=\frac{0}{40}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+11}{2*20}=\frac{22}{40}
=11/20
$